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Find the angle made by the following vector with the coordinates axes: `(hati+hatj+hatk)``(hatj-hatk)` `(hati-4hatj+8hatk)` |
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Answer» Correct Answer - (i) `cos^(-1)((1)/(sqrt3)),cos^(-1)((1)/(sqrt3)),cos^(-1)((1)/(sqrt3))` (ii) `(pi)/(2),(pi)/(4),(3pi)/(4)` (iii) `cos^(-1)""((1)/(9)),cos^(-1)((4)/(9)),cos^(-1)((8)/(9))` (i) Let `veca=hati-hatj+hatk`. `cosalpha=((hati-hatj+hatk)*hati)/(|hati-hatj+hatk||hati|)=(1)/(sqrt3),cosbeta=((hati-hatj+hatk)*hatj)/(|hati-hatj+hatk||hatj|)=(-1)/(sqrt3)` and `cosgamma=((hati-hatj+hatk)*hatk)/(|hati-hatj+hatk||hatk|)=(1)/(sqrt3)`. |
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