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Find the approximate value of climb angle if Thrust is 1500N, drag is 1000N and weight of the aircraft is 2500N.(a) 11.53 degree(b) 30 degree(c) 40 degree(d) 1 degreeI got this question in exam.Enquiry is from Flight Mechanics topic in portion Performance and Flight Mechanics of Aircraft Design

Answer» CORRECT CHOICE is (a) 11.53 DEGREE

To explain: Given, steady climb, Thrust=1500N, drag D=1000N, WEIGHT W=2500N.

Climb angle = arcsine [{T-D}/W]

= arcsine [{1500-1000}/2500] = 11.53 degree.


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