1.

Find the area of the shaded region given in figure.

Answer»

SOLUTION :Join JK, KL, LM and MJ.
There are FOUR equally semi - circlesand LMHK formed a SQUARE.
`:. FH = 14 - (3 + 3) = 8 cm`
So, the side of square should be 4 cm and radius of semi - circle of both endsare 2 cm each.
`:.` AREA of square JKLM = `(4)^(2) = 16 cm^(2)`
Area of semi - circle HJM = `(pir^(2))/(2)`
= `(pixx(2)^(2))/(2)=2pi cm^(2)`
`:.` Area of four semi - circle = `4xx6.28 = 25 12 cm^(2)`
Now, area of square ABCD = `(14)^(2) = 196 cm^(2)`
`:.` Area of shaded region = Area of square ABCD
- [Area of four semi - circle + Area of square JKLM]
= `196 - [8pi + 16] = 196 - 16 - 8pi`
= `(180 - 8 pi) cm^(2)`
Hence , the required of the shaded region is `(180 - 8 pi)cm^(2)` .


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