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Find the area of the triangle whose vertices are: A(-2, 4), B(2, -6) and C(5, 4) |
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Answer» Area of triangle = \(\frac{1}{2}\)\(\begin{bmatrix}x_1 & y_1 & 1 \\[0.3em]x_2 & y_2 & 1 \\[0.3em]x_3 &y_3 & 1\end{bmatrix}\) = \(\frac{1}{2}\)\(\begin{bmatrix}-2 & 4& 1 \\[0.3em]2 & -6 & 1 \\[0.3em]5 &4& 1\end{bmatrix}\) Expanding with C3 = \(\frac{1}{2}\)[(8 + 30) - (-8 - 20) + (12 - 8)] = \(\frac{1}{2}\) [38 + 28 + 4] = \(\frac{68}{2}\) = 34 sq. units |
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