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If A,B,C are the angles of a non right angled triangle ABC. Then find the value of:`|[tanA,1,1],[1,tanB,1],[1,1,tanC]|` |
Answer» Since the determinant is sysmmetrical it is easier to expand by Sarrus rule. Hence. `|{:(tanA,,1,,1),(1,,tanB,,1),(1,,1,,tanC):}|` = tan A tan B tan C +1+1 - tan A -tan B-tan C =2 [as in a triangle tan A+ tan B + tan C= tan A tan B tan C) |
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