1.

Using the property of determinants and without expanding in questions 1 to 7 prove that , `|{:(a-b,b-c,c-a),(b-c,c-a,a-b),(c-a,a-b,b-c):}|=0`

Answer» `L.H.S.=|{:(a-b,b-c,c-a),(b-c,c-a,a-b),(c-a,a-b,b-c):}|=|{:(0,b-c,c-a),(0,c-a,a-b),(0,a-b,b-c):}|`
`((C_(1)toC_(1)+C_(2)+C_(3))`
`=0 " "(because" all elements of "C_(1)" are zero)`
=R.H.S.


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