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Value of \(\begin{vmatrix}cos50^o &sin10^o \\[0.3em]sin50^o & cos10^o \\[0.3em]\end{vmatrix}\) is :(a) 0(b) 1(c) 1/2(d) – 1/2

Answer»

Answer is (c)

  \(\begin{vmatrix}cos50^o &sin10^o \\[0.3em]sin50^o & cos10^o \\[0.3em]\end{vmatrix}\) 

= cos 50° cos 10° – sin 50° sin 10°

= cos (50° + 10°)

= cos 60° = 1/2​​​​​



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