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Find the binding energy of `_26^56 Fe`. Atomic mass of `^56 Fe` is `55.9349 u` and that of `^1 H` is `1.00783 u`. Mass of neutron `= 1.00867 u`. |
Answer» The number of protons in `(._(26)^(56)Fe)=26` and the number of neutrons `=56-26=30`. The binding energy of `(._(26)^(56)Fe) =26` and the number of neutrons `=56-26 =30`. The binding energy `(._(26)^(56)Fe)` `=[26 xx 1.0078 u+30 xx 1.00867 u-55.9349 u]c^(2)` `=(0.52878 u)c^(2)` `=(0.52878 u)(931 MeV//u) =492 MeV.` |
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