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Find the co-ordinates of the points fo trisection of the line joining the points (3,-2) and (-3, -4). |
Answer» Solution :LET P `(a, b) and Q(c, d)` TRISECT the line joining the POINTS `A(3, -2) and B(-3, -4)`. Now, point P (a, b) divides the line AB in the ratio `1: 2`. ![]() `therefore""a=(1(-3)+2(3))/(1+2)=(3)/(3)=1` `""b=(1(-4)+2(-2))/(1+2)=-(8)/(3)` Therefore, co-ordinates of point P = `(1, -(8)/(3))` `Q(c, d)` divides the line AB in the ratio 2 :1. `therefore""c=(2(-3)+1(3))/(2+1)=-1` `""d=(2(-4)+1(-2))/(2+1)=(-10)/(3)` Therfore, co-ordinates of `Q=(-1, (-10)/(3))` `therefore` Co-ordinates of points of trisection of AB = `=(1, (-8)/(3))and (-1, (-10)/(3))` |
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