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Find the current through 3Ω resistor in the circuit shown below.(a) 1(b) 2(c) 3(d) 4This question was addressed to me in an interview for job.Enquiry is from Reciprocity Theorem topic in section Useful Theorems in Circuit Analysis of Network Theory

Answer»

Right choice is (b) 2

The explanation is: The 6Ω resistor is PARALLEL to 3Ω resistor and the RESULTANT is in series with 2Ω resistor. Total CURRENT from source = 12/(2+(6│|3))=3A. Current through 3Ω resistor = 3 × 6/(6+3)=2A.



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