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Find the current through 6Ω resistor in the circuit shown below.(a) 1(b) 1.43(c) 2(d) 2.43This question was posed to me at a job interview.My doubt stems from Norton’s Theorem in section Useful Theorems in Circuit Analysis of Network Theory

Answer» CORRECT CHOICE is (b) 1.43

To EXPLAIN: The current passing through the 6Ω resistor and the voltage ACROSS it DUE to Norton’s equivalent circuit is I = 4×3.33/(6+3.33) = 1.43A.


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