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Find the density of `._(6)^(12)C` nucleus. Take atomic mass of `._(6)^(12)C` as `12.00 am u` Take `R_(0) =1.2 xx10^(-15) m` . |
Answer» Correct Answer - `2.4 xx 10^(7) kgm^(-3)` The radius of `._(6)^(12)C` is `12 a.m.u.` Neglecting the masses and binding energies of the six electrons. Nuclear density `=(m)/((4)/(3)pi R^(3)) =(12 xx 1.66 xx 10^(-27))/(((4)/(3) pi)(2.7 xx 10^(-15))^(3))` `=2.4 xx 10^(17)` kg m^(-3)` . |
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