1.

Find the density of `._(6)^(12)C` nucleus. Take atomic mass of `._(6)^(12)C` as `12.00 am u` Take `R_(0) =1.2 xx10^(-15) m` .

Answer» Correct Answer - `2.4 xx 10^(7) kgm^(-3)`
The radius of `._(6)^(12)C` is `12 a.m.u.` Neglecting the masses and binding energies of the six electrons.
Nuclear density `=(m)/((4)/(3)pi R^(3)) =(12 xx 1.66 xx 10^(-27))/(((4)/(3) pi)(2.7 xx 10^(-15))^(3))`
`=2.4 xx 10^(17)` kg m^(-3)` .


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