1.

Find the directivity when the half power beam widths are 45° and 60° in perpendicular planes.(a) 12.58(b) 17.98(c) 22.91(d) 15.28The question was asked during an internship interview.This interesting question is from Half Power Beam Width in portion Antenna Beam Width & Input Impedance of Antennas

Answer»

The CORRECT option is (d) 15.28

Easy explanation: DIRECTIVITY in TERMS of HPBW (in degrees) is given by \(D=\frac{41257}{θ_E θ_H} =\frac{41257}{45° × 60°}=15.28\)



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