1.

If the HPBW is 30° then FNBW is approximately _____(a) 60°(b) 30°(c) 15°(d) 20°The question was posed to me during an online interview.My question is taken from First Null Beam Width in chapter Antenna Beam Width & Input Impedance of Antennas

Answer»

The CORRECT ANSWER is (a) 60°

For EXPLANATION I WOULD say: FNBW ≈ 2HPBW=2×30°=60°



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