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What is the Beam area in radians when the HPBW in perpendicular planes are given by 60°, 30°?(a) \(\frac{\pi^2}{8}\)(b) \(\frac{\pi}{2}\)(c) \(\frac{\pi^2}{18}\)(d) 2This question was addressed to me by my school teacher while I was bunking the class.The question is from Half Power Beam Width topic in chapter Antenna Beam Width & Input Impedance of Antennas

Answer»

Right option is (c) \(\frac{\pi^2}{18}\)

Easy explanation: Beam AREA B=θE θH=60°×30°=\(\frac{\pi}{3}×\frac{\pi}{6}=\frac{\pi^2}{18}\)



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