InterviewSolution
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InterviewSolution
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Find the distance of (2, 3) from the line x + 4y = 5 |
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Answer» Given line is x + 4y – 5 = 0 Here, A = 1, B = 4, C = – 5 and the given point is (x1, y1) = (2, 3) ∴ Distance, d = \(\bigg|\frac{A_1 x + B_1 y + C_1}{\sqrt{A^2 + B^2}}\bigg|\) = \(\bigg|\frac{1.2 + 4.3 + 5}{\sqrt{1^2 + 4^2}}\bigg|\) = \(\frac{9}{\sqrt{17}}\) = \(\frac{9\sqrt{17}}{17}\) units |
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