Find the equation of a line making an angle of 150° with the x–axis

1.	Find the equation of a line making an angle of 150° with the x–axis and cutting off an intercept 2 from y–axis.
Answer» Given: A line which makes an angle of 150° with the x–axis and cutting off an intercept at 2 By using the formula, The equation of a line is y = mx + c We know that angle, θ = 150° The slope of the line, m = tan θ Where, m = tan 150° = -1/ √3 Coordinate of y–intercept is (0, 2) The required equation of the line is y = mx + c Now substitute the values, we get y = -x/√3 + 2 √3y – 2√3 + x = 0 x + √3y = 2√3 ∴ The equation of line is x + √3y = 2√3

Find the equation of a line making an angle of 150° with the x–axis and cutting off an intercept 2 from y–axis.

Answer»

Given: A line which makes an angle of 150° with the x–axis and cutting off an intercept at 2

By using the formula,

The equation of a line is y = mx + c

We know that angle, θ = 150°

The slope of the line, m = tan θ

Where, m = tan 150°

= -1/ √3

Coordinate of y–intercept is (0, 2)

The required equation of the line is y = mx + c

Now substitute the values, we get

y = -x/√3 + 2

√3y – 2√3 + x = 0

x + √3y = 2√3

∴ The equation of line is x + √3y = 2√3