1.

Find the equation of a line passing through (3, -2) and perpendicular to the line x – 3y + 5 = 0.

Answer»

Given: equation is perpendicular to x – 3y + 5 = 0 and passes through (3,-2) 

To find: Equation of required line. 

Explanation: 

The equation of the line perpendicular to x − 3y + 5 = 0 is 

3x + y + λ = 0, 

Where λ is a constant. 

It passes through (3, − 2). 

9 – 2 + λ = 0 

⇒ λ = - 7 

Substituting λ = − 7 in 3x + y + λ = 0, 

Hence, we get 3x + y – 7 = 0, which is the required line.



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