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Find the equation of a line passing through the point (2, 3) and parallel to the line 3x– 4y + 5 = 0. |
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Answer» Given: equation is parallel to 3x − 4y + 5 = 0 and pass through (2, 3) To find: Equation of required line. Explanation: The equation of the line parallel to 3x − 4y + 5 = 0 is 3x – 4y + λ = 0, Where, λ is a constant. It passes through (2, 3). ∴6 – 12 + λ = 0 ⇒ λ = 6 Hence, the required line is 3x − 4y + 6 = 0. |
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