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Find the equation of a line whose slope is 4 and which passes through the point (5, - 7) |
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Answer» As slope is given m = 4 and passing through (5, - 7).using slope - intercept form of equation of line, we will find value of intercept first y = mx + c ………..(1) - 7 = 4(5) + c - 7 = 20 + c c = - 7 - 20 c = - 27 Putting the value of c in equation (1), we have y = 4x + ( - 27) y = 4x - 27 4x - y - 27 = 0 So, the required equation of line is 4x - y - 27 = 0. |
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