1.

Find the equation of circle with radius r, whose centre lies in 1st quadrant and touches y-axis at a distance of h from the origin. Find the equation of other tangent which passes through origin.

Answer»

Centre of circle = (r, h)

Radius of circle = r

Thus, equation of circle

(x – r)2 + (y – h)2 = r2

Let tangent OB touches the circle at B. 

Tangent passes through origin. 

Let tangent touches the circle at point (x1,y1).

∴ Equation of tangent at point of circle,

xx1 + yy1 + g(x + x1) + f(y + y1) + c = 0

xx1 + yy1 – r(x + x1) + h(y + y1) + h2 = 0

Since the line passes through origin.

∴ x × 0 + y × 0 – r(x + 0) – h(y + 0) + h2 = 0

⇒ – rx – hy + h2 = 0

⇒ rx + hy – h2 = 0

This is required equation.



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