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Find the equation of circle with radius r, whose centre lies in 1st quadrant and touches y-axis at a distance of h from the origin. Find the equation of other tangent which passes through origin. |
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Answer» Centre of circle = (r, h) Radius of circle = r Thus, equation of circle (x – r)2 + (y – h)2 = r2 Let tangent OB touches the circle at B. Tangent passes through origin. Let tangent touches the circle at point (x1,y1). ∴ Equation of tangent at point of circle, xx1 + yy1 + g(x + x1) + f(y + y1) + c = 0 xx1 + yy1 – r(x + x1) + h(y + y1) + h2 = 0 Since the line passes through origin. ∴ x × 0 + y × 0 – r(x + 0) – h(y + 0) + h2 = 0 ⇒ – rx – hy + h2 = 0 ⇒ rx + hy – h2 = 0 This is required equation. |
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