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Find the length of major axis and minor axis of the ellipse 16x2 + 25y2 = 400. |
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Answer» Given equation of the ellipse is 16x2 + 25y2 = 400 \(= \frac{x^2}{25}+\frac{y^2}{16}=1\\=\frac{x^2}{5^2}+\frac{y^2}{4^2}=1\) a = 5,b = 4 ∴ Length of major axis = 2a = 10 And length of minor axis = 2b = 8. |
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