1.

Find the length of major axis and minor axis of the ellipse 16x2 + 25y2 = 400.

Answer»

Given equation of the ellipse is 16x2 + 25y2 = 400

\(= \frac{x^2}{25}+\frac{y^2}{16}=1\\=\frac{x^2}{5^2}+\frac{y^2}{4^2}=1\) 

a = 5,b = 4

∴ Length of major axis = 2a = 10 

And length of minor axis = 2b = 8.



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