Find the equation of the line for which p = 5 and ∝ = 1350

1.	Find the equation of the line for which p = 5 and ∝ = 1350
Answer» Given: p = 5 and ∝ = 1350 Here p is the perpendicular that makes an angle ∝ with positive direction of x-axis, hence the equation of the straight line is given by: Formula used: x cos ∝ + y sin ∝ = p x cos 1350 + y sin 1350 = 5 i.e; cos 1350 = cos ((4 360) - 90) = cos((4×2π) - 90)= cos 90 similarly, sin 1350 = sin ((4 360) - 90) = sin((4×2π ) - 90) = -sin 90 hence, x cos 90 + y (–sin 90) = 5 x × (0) - y ×1 = 5 Hence The required equation of the line is y = -5.

Answer»

Given: p = 5 and ∝ = 1350

Here p is the perpendicular that makes an angle ∝ with positive direction of x-axis, hence the equation of the straight line is given by:

Formula used:

x cos ∝ + y sin ∝ = p

x cos 1350 + y sin 1350 = 5

i.e; cos 1350 = cos ((4 360) - 90) = cos((4×2π) - 90)= cos 90

similarly, sin 1350 = sin ((4 360) - 90) = sin((4×2π ) - 90) = -sin 90

hence, x cos 90 + y (–sin 90) = 5

x × (0) - y ×1 = 5

Hence The required equation of the line is y = -5.

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