InterviewSolution
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InterviewSolution
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Find the equation of the line having inclination 135° and making x-intercept 7. |
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Answer» Given, Inclination of line = 0 = 135° ∴ Slope of the line (m) = tan 0 = tan 135° = tan (90° + 45°) = – cot 45° = – 1 x-intercept of the required line is 7. ∴ The line passes through (7, 0). Equation of the line in slope point form is y1 – y = m(x – x1) ∴ The equation of the required line is y — 0 = – 1 (x – 7) ∴ y = -x + 7 ∴ x + y – 7 = 0 y= aX+b:-->, where a is the slope of the line and b, is the y-intercept.when x takes a value of 0 then aX = 0 and then y =b (that's why b is the y-intercept ). Accordingly, calculate the slope which is tan(theta) ( sin(theta)/cos(theta)= y/x) put that value to be the (a) in the equation, and put the y-intercept (+7) in place of b final eq--> y= tan(135)X+7 |
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