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Find the equation of the line passing through (1,2) and parallel to the line y = 3x – 1 |
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Answer» The given is Y = 3x – 1 ⇒ 3x – y – 1 = 0 …(1) ∴ Any line parallel to (1) is written as 3x – y + γ = 0 …(2) Since the line passes through (1, 2), 3(1) – 1 + γ = 0 ⇒ γ = – 1 ∴ The line is 3x – y – 1 = 0, which is itself. |
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