Find the equation of the line passing through (2, 2√3) and inclined

1.	Find the equation of the line passing through (2, 2√3) and inclined with x – axis at an angle of 75°.
Answer» A line which is passing through (2,2√3), the angle is 75°. To Find: The equation of a straight line. Formula used: The equation of line is [y – y₁ = m(x – x₁)] Explanation: Here, angle, θ = 75° So, The slope of the line, m = tan θ m = tan 75° m = 3.73 = 2 + √3 The line passing through (x₁,y₁) = (2,2√3) The required equation of the line is y – y₁= m(x – x₁) y – 2√3 = 2 + √3 (x – 2) y – 2√3 = (2 + √3)x – 7.46 (2 + √3)x – y – 4 = 0 Hence, The equation of the line is (2 + √3)x – y – 4 = 0

Find the equation of the line passing through (2, 2√3) and inclined with x – axis at an angle of 75°.

Answer»

A line which is passing through (2,2√3), the angle is 75°.

To Find: The equation of a straight line.

Formula used: The equation of line is [y – y₁ = m(x – x₁)]

Explanation: Here, angle, θ = 75°

So, The slope of the line, m = tan θ

m = tan 75°

m = 3.73 = 2 + √3

The line passing through (x₁,y₁) = (2,2√3)

The required equation of the line is y – y₁= m(x – x₁)

y – 2√3 = 2 + √3 (x – 2)

y – 2√3 = (2 + √3)x – 7.46

(2 + √3)x – y – 4 = 0

Hence, The equation of the line is (2 + √3)x – y – 4 = 0