Find the equation of the line perpendicular to the line x – 7y + 5 =

1.	Find the equation of the line perpendicular to the line x – 7y + 5 = 0 and having x-intercept 3.
Answer» Given line is x-7y + 5 = 0 Slope = m = - a/b = -(1/-7) = 1/7 Slope of the line perpendicular to the given line = – 7 (∵ m₁ x m₂=-1) Since x-intercept is 3 then (3, 0) is the point on the required line. ∴ Required equation the line passing through (3, 0) having slope – 7 is, y – 0 = -7(x - 3) i.e., 7x ± y – 21 = 0

Find the equation of the line perpendicular to the line x – 7y + 5 = 0 and having x-intercept 3.

Answer»

Given line is x-7y + 5 = 0

Slope = m = - a/b = -(1/-7) = 1/7

Slope of the line perpendicular to the given line = – 7

(∵ m₁ x m₂=-1)

Since x-intercept is 3 then (3, 0) is the point on the required line.

∴ Required equation the line passing through (3, 0) having slope – 7 is, y – 0 = -7(x - 3)

i.e., 7x ± y – 21 = 0