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Find the equation of the line, which passes through the point (2, 3) and makes an angle of 30° with the positive direction of x-axis. |
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Answer» Given, inclination of the line, θ = 30°. Slope of the line, m = tan 30° = \(\frac{1}{\sqrt{3}}\) Equation of a line in one-point form is y – y0 = m(x – x0) Since m = \(\frac{1}{\sqrt{3}}\) and (x0, y0) = (2, 3) ∴ y − 3 = \(\frac{1}{\sqrt{3}}\)(x − 2) ⇒ \(\sqrt{3}\)y − 3\(\sqrt{3}\) = x – 2 ⇒ x − \(\sqrt{3}\)y + (2 − 3\(\sqrt{3}\)) = 0, is the required equation of the line. |
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