Find the equation of the parallel to x–axis and passing through (3,

1.	Find the equation of the parallel to x–axis and passing through (3, – 5).
Answer» Given, A line which is parallel to x–axis and passing through (3, – 5) To Find: The equation of the line. Formula used: The equation of line is [y – y₁ = m(x – x₁)] Explanation: Here, The line is parallel to the x–axis, So, The parallel lines have equal slopes, And, the slope of x–axis is always 0, then The slope of line, m = 0 Coordinates of line are (x₁, y₁) = (3, – 5) The equation of line = y – y₁= m(x – x₁) By putting the values, we get y – (– 5) = 0(x – 3) y + 5 = 0 Hence, The equation of line is y + 5 = 0

Find the equation of the parallel to x–axis and passing through (3, – 5).

Answer»

Given, A line which is parallel to x–axis and passing through (3, – 5)

To Find: The equation of the line.

Formula used: The equation of line is [y – y₁ = m(x – x₁)]

Explanation: Here, The line is parallel to the x–axis,

So, The parallel lines have equal slopes,

And, the slope of x–axis is always 0, then

The slope of line, m = 0

Coordinates of line are (x₁, y₁) = (3, – 5)

The equation of line = y – y₁= m(x – x₁)

By putting the values, we get

y – (– 5) = 0(x – 3)

y + 5 = 0

Hence, The equation of line is y + 5 = 0