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Find the equation of the straight line passing through the point (6, 2) and having slope – 3. |
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Answer» Given, A straight line passing through the point (6, 2) and the slope is – 3 By using the formula, Here, the line is passing through (6, 2) It is given that, the slope of line, m = –3 Coordinates of line are (x1, y1) = (6,2) The equation of line = y – y1 = m(x – x1) Now, substitute the values, we get y – 2 = – 3(x – 6) y – 2 = – 3x + 18 y + 3x – 20 = 0 ∴ The equation of line is 3x + y – 20 = 0 |
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