Find the equation of the straight line passing through (–2, 3) and i

1.	Find the equation of the straight line passing through (–2, 3) and indicated at an angle of 45° with the x – axis.
Answer» Given: A line which is passing through (–2, 3), the angle is 45°. By using the formula, The equation of line is [y – y₁ = m(x – x₁)] Here, angle, θ = 45° The slope of the line, m = tan θ m = tan 45° = 1 The line passing through (x₁, y₁) = (–2, 3) The required equation of line is y – y₁ = m(x – x₁) Now, substitute the values, we get y – 3 = 1(x – (– 2)) y – 3 = x + 2 x – y + 5 = 0 ∴The equation of line is x – y + 5 = 0

Find the equation of the straight line passing through (–2, 3) and indicated at an angle of 45° with the x – axis.

Answer»

Given:

A line which is passing through (–2, 3), the angle is 45°.

By using the formula,

The equation of line is [y – y₁ = m(x – x₁)]

Here, angle, θ = 45°

The slope of the line, m = tan θ

m = tan 45°

= 1

The line passing through (x₁, y₁) = (–2, 3)

The required equation of line is y – y₁ = m(x – x₁)

Now, substitute the values, we get

y – 3 = 1(x – (– 2))

y – 3 = x + 2

x – y + 5 = 0

∴The equation of line is x – y + 5 = 0