1.

Find the equation to the straight line(i) cutting off intercepts 3 and 2 from the axes.(ii) cutting off intercepts -5 and 6 from the axes.

Answer»

(i) Cutting off intercepts 3 and 2 from the axes.

Given:

a = 3, b = 2

Let us find the equation of line cutoff intercepts from the axes.

By using the formula,

The equation of the line is x/a + y/b = 1

x/3 + y/2 = 1

By taking LCM,
2x + 3y = 6

∴ The equation of line cut off intercepts 3 and 2 from the axes is 2x + 3y = 6

(ii) Cutting off intercepts -5 and 6 from the axes.

Given:

a = -5, b = 6

Let us find the equation of line cutoff intercepts from the axes.

By using the formula,

The equation of the line is x/a + y/b = 1

x/-5 + y/6 = 1

By taking LCM,
6x – 5y = -30

∴ The equation of line cut off intercepts 3 and 2 from the axes is 6x – 5y = -30



Discussion

No Comment Found