Find the equation to the straight line which cuts off equal positive i

1.	Find the equation to the straight line which cuts off equal positive intercepts on the axes and their product is 25
Answer» Concept Used: The equation of the line with intercepts a and b is \(\frac{x}{a}+\frac{y}{b}=1\) To find: The equation of the line which cutoff intercepts on the axes. Given: Here a = b and ab = 25 Explanation: ∴ a² = 25 ⇒ a = 5 since we are to take only positive value of intercepts Hence, the equation of the required line is Formula used: \(\frac{x}{a}+\frac{y}{b}=1\) \(\frac{x}{5}+\frac{y}{5}=1\) ⇒ x + y = 5 Hence, the equation of line is x + y = 5

Find the equation to the straight line which cuts off equal positive intercepts on the axes and their product is 25

Answer»

Concept Used:

The equation of the line with intercepts a and b is \(\frac{x}{a}+\frac{y}{b}=1\)

To find:

The equation of the line which cutoff intercepts on the axes.

Given:

Here a = b and ab = 25

Explanation: ∴ a² = 25

⇒ a = 5 since we are to take only positive value of intercepts

Hence, the equation of the required line is

Formula used: \(\frac{x}{a}+\frac{y}{b}=1\)

\(\frac{x}{5}+\frac{y}{5}=1\)

⇒ x + y = 5

Hence, the equation of line is x + y = 5