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Find the equation to the straight line which cuts off equal positive intercepts on the axes and their product is 25. |
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Answer» Given: a = b and ab = 25 Let us find the equation of the line which cutoff intercepts on the axes. ∴ a2 = 25 a = 5 [considering only positive value of intercepts] By using the formula, The equation of the line with intercepts a and b is x/a + y/b = 1 x/5 + y/5 = 1 By taking LCM x + y = 5 |
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