Find the equation to the straight line which passes through the point

1.	Find the equation to the straight line which passes through the point (5, 6) and has intercepts on the axes Equal in magnitude but opposite in sign
Answer» Given: Here, b = -a To find: The equation of line cutoff intercepts from the axes. Explanation: So, the equation of the line is Formula used: \(\frac{x}{a}+\frac{y}{b}=1\) \(\frac{x}{a}+\frac{y}{b}=1\) \(\frac{x}{a}+\frac{y}{-a}=1\) ⇒ x – y = a The line passes through the point (5, 6) So equation satisfy the points, ⇒ 5 – 6 = a ⇒ a = -1 The equation of the line is x – y = -1

Find the equation to the straight line which passes through the point (5, 6) and has intercepts on the axes Equal in magnitude but opposite in sign

Answer»

Given:

Here, b = -a

To find:

The equation of line cutoff intercepts from the axes.

Explanation:

So, the equation of the line is

Formula used: \(\frac{x}{a}+\frac{y}{b}=1\)

\(\frac{x}{a}+\frac{y}{b}=1\)

\(\frac{x}{a}+\frac{y}{-a}=1\)

⇒ x – y = a

The line passes through the point (5, 6) So equation satisfy the points,

⇒ 5 – 6 = a

⇒ a = -1

The equation of the line is x – y = -1