InterviewSolution
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Find the equations of the straight lines which pass through (4, 3) and are respectively parallel and perpendicular to the x–axis. |
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Answer» Given: A line which is perpendicular and parallel to x–axis respectively and passing through (4, 3) By using the formula, The equation of line: [y – y1 = m(x – x1)] Let us consider, Case 1: When Line is parallel to x–axis The parallel lines have equal slopes, And, the slope of x–axis is always 0, then The slope of line, m = 0 Coordinates of line are (x1, y1) = (4, 3) The equation of line is y – y1 = m(x – x1) Now substitute the values, we get y – (3) = 0(x – 4) y – 3 = 0 Case 2: When line is perpendicular to x–axis The line is perpendicular to the x–axis, then x is 0 and y is – 1. The slope of the line is, m = y/x = -1/0 Coordinates of line are (x1, y1) = (4, 3) The equation of line = y – y1 = m(x – x1) Now substitute the values, we get y – 3 = (-1/0) (x – 4) ∴ The equation of line when it is parallel to x – axis is y = 3 and it is perpendicular is x = 4. |
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