Find the following products: 4/3a (a2 + b2 – 3c2)

1.	Find the following products: 4/3a (a2 + b2 – 3c2)
Answer» Given, 4/3a (a² + b² – 3c²) = 4/3a (a² + b² – 3c²) = (4/3a × a²) + (4/3a × b²) – (4/3a × 3c²) = 4/3a³ + 4/3ab² – 4ac²

Answer»

Given,

4/3a (a² + b² – 3c²)

= 4/3a (a² + b² – 3c²)

= (4/3a × a²) + (4/3a × b²) – (4/3a × 3c²)

= 4/3a³ + 4/3ab² – 4ac²

Discussion

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