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Subtract the sum of 3l – 4m – 7n2 and 2l + 3m – 4n2 from the sum of 9l + 2m – 3n2 and -3l + m + 4n2…. |
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Answer» Sum of 3l – 4m – 7n2 and 2l + 5m – 4n2 = 3l – 4m – 7n2 + 2l + 3m – 4n2 = 3l + 2l – 4m + 3m – 7n2 – 4n2 = 5l – m – 11n2 ……………………..equation (1) Sum of 9l + 2m – 3n2 and -3l + m + 4n2 = 9l + 2m – 3n2 + (-3l + m + 4n2) = 9l – 3l + 2m + m – 3n2 + 4n2 = 6l + 3m + n2 ……………………….equation (2) Let us subtract equation (i) from (ii), we get = 6l + 3m + n2 – (5l – m – 11n2) = 6l – 5l + 3m + m + n2 + 11n2 = l + 4m + 12n2 |
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