1.

Find the following products:(i)  2a3 (3a + 5b)(ii) -11a (3a + 2b)(iii) -5a (7a – 2b)(iv) -11y2 (3y + 7)

Answer»

(i) 2a3 (3a + 5b)

= 2a3 (3a + 5b)

= (2a3 × 3a) + (2a3 × 5b)

= 6a4 + 10a3b

(ii) -11a (3a + 2b)

= -11a (3a + 2b)

= (-11a × 3a) + (-11a × 2b)

= -33a2 – 22ab

(iii) -5a (7a – 2b)

= -5a (7a – 2b)

= (-5a × 7a) – (-5a × 2b)

= -35a2 + 10ab

(iv) -11y2 (3y + 7)

= -11y2 (3y + 7)

= (-11y2 × 3y) + (-11y2 × 7)

= -33y3 – 77y2



Discussion

No Comment Found