1.

Find the function f3 (t) from the time t = 3 to 4 sec.(a) (20t – 40) [u (t-3) – u (t-4)](b) (20t + 40) [u (t-3) – u (t-4)](c) (20t + 40) [u (t-3) + u (t-4)](d) (20t – 40) [u (t-3) + u (t-4)]I got this question during an interview.This question is from Definition of the Laplace Transform topic in section Intoduction to the Laplace Transform of Network Theory

Answer»

Correct answer is (a) (20T – 40) [u (t-3) – u (t-4)]

For EXPLANATION: From the graph, f3 (t) = 20t – 40 for 3 < t < 4. In terms of unit step FUNCTION, f3 (t) = (20t – 40) [u (t-3) – u (t-4)]. This function TURN off at t = 3, turn off at t = 4.



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