Find the how many moles of atoms are there in : (i) 2 g of nitrogen (ii) 23 g of sodium (iii) 40 g of calcium (iv) 1.4 g of lithium (v) 32 g of sulphur

Find the how many moles of atoms are there in : (i) 2 g of nitrogen

1.	Find the how many moles of atoms are there in : (i) 2 g of nitrogen (ii) 23 g of sodium (iii) 40 g of calcium (iv) 1.4 g of lithium (v) 32 g of sulphur
Answer» Solution :(i) 2G of nitrogen `"Number of moles"=("Mass")/("atomic mass")` `"Atomic mass of Nitrogen"=14,"Mass of Nitrogen"=2g` `therefore " Number of moles "=(2)/(14)="0.142 moles of Nitrogen"` (ii) 23 g of sodium Atomic mass of sodium = 23 Mass of sodium = 23 g `"Number of moles"=("Mass")/("atomic mass")=(23)/(23)=1" moles of calcium"` (iv) 1.4 g of lithium Atomic mass of lithium = 7 `"Number of moles"=("Mass")/("atomic mass")=(1.4)/(7)` `=(2)/(1)=0.2" MOLE of lithium"` (v ) 32 g of sulphur Atomic mass of sulphur = 32 Mass of sulphur = 32g `"Number of moles"=("Mass")/("atomic mass")=(32)/(32)="1 mole of sulphur"`