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Find the Laplace transform of the function f (t) = tsin2t.(a) 4s/(s^2+4)^2(b) -4s/(s^2+4)^2(c) -4s/(s^2-4)^2(d) 4s/(s^2-4)^2The question was asked during an online interview.Question is from Operational Transforms in division Intoduction to the Laplace Transform of Network Theory

Answer»

Right option is (a) 4s/(s^2+4)^2

Explanation: The LAPLACE transform of the FUNCTION of sin2t is L(sin2t)=2/(s^2+4). So the Laplace transform of the function F (t) = tsin2t is L(tsin2t) = -d/ds [2/(s^2+4)] = 4s/(s^2+4)^2.



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