1.

Find the mean median of the following frequency distrbution : Also, find the mode of the following data.

Answer»

Solution :We have

Let assumed `A=55 ,h=10. sumf= 50 and sumfu=-27`

`"Mean"barx=A+[hxx(sum(fu))/(sumf)]`
`barx=55+(10xx(-27)/(50))`
`barx=55-5.4`
`barx=49.6`
Here, N=50 `rarr (N)/(2)=(50)/(2)=25`
Cumulative FREQUENCY just greater than 25 is 36 and the corresponding class is 50-60
`:. l_(1)=50,f=12ml_(2)=60,C=24,i=60-50=10`
Now, `"MEDIAN"(M)=l_(1)+(((N)/(2)-C))/(f)XXI`
`=50+(10)/(12)(25-24)=50+(10)/(12)`
`=50+0.83=50.83`
Mode =3(Median)-2(Mean)
Mode = `3xx50.83-2xx49.60`
`=152.49-99.20=53.29`


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