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Find the product of the following binomials:(i) (4x/5 – 3y/4) (4x/5 + 3y/4)(ii) (2x + 3/y) (2x – 3/y)(iii) (2a3 + b3) (2a3 – b3) |
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Answer» (i) (4x/5 – 3y/4) (4x/5 + 3y/4) = 4x/5 (4x/5 + 3y/4) – 3y/4 (4x/5 + 3y/4) = 16/25x2 + 12/20yx – 12/20xy – 9y2/16 = 16/25x2 – 9/16y2 (ii) (2x + 3/y) (2x – 3/y) = 2x (2x – 3/y) + 3/y (2x – 3/y) = 4x2 – 6x/y + 6x/y – 9/y2 = 4x2 – 9/y2 (iii) (2a3 + b3) (2a3 – b3) = 2a3 (2a3 – b3) + b3 (2a3 – b3) = 4a6 – 2a3b3 + 2a3b3 – b6 = 4a6 – b6 |
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