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Find the quality factor of the following circuit.(a) 2.24(b) 3.34(c) 4.44(d) 5.54This question was addressed to me in my homework.The above asked question is from Parallel Resonance in section Resonance & Magnetically Coupled Circuit of Network Theory

Answer»

The correct choice is (a) 2.24

Easy EXPLANATION: The quality factor of the circuit is Q = XL/R = 2πfrL/R. Given F = 7.12 Hz and L = 5H and R = 100. On substituting the given VALUES in the equation we get the quality factor = (6.28×7.12×5)/100 = 2.24.



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