1.

Find the range of `f(x)=1/(2abscosx-3)`

Answer» Correct Answer - [-1, 1/3]
`0leabscosxle1`
`rArr 0le2abscosxle2`
`rArr-3le2abscosx-3le-1`
`rArr 1/(2abs(cosx)-3)in[-1,-1//3]`


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