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Find the range of `f(x)=1/(2abscosx-3)` |
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Answer» Correct Answer - [-1, 1/3] `0leabscosxle1` `rArr 0le2abscosxle2` `rArr-3le2abscosx-3le-1` `rArr 1/(2abs(cosx)-3)in[-1,-1//3]` |
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