Find the range of `f(x)=cos^2x+sec^2x`. – InterviewSolution

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1.	Find the range of `f(x)=cos^2x+sec^2x`.
Answer» We have `f(x)=cos^2x=sec^2x` `=(cos-secx)^2+2cosxsecx` `=2+(cosx-secx)^2ge2`

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