1.

Find the ratio of the effort required to raise a given load to a certain height, when the angle of inclination of a plank is changed from 60^(@) to 45^(@). Also find the lengths of the plank in the two cases given the load has tobe raised to a height of 5 m.

Answer»

Solution :(i) RELATION between mechanical advantage (M.A.) and angle of inclination `(theta)`
(ii) Load is constantand also height is constant
(iii) Relate mechanical advantage to thecorrespondingtrigonometric RATIO of the angle of inclination.
(vi) Also relate mechanicaladvantage to load and effort.
(v) From the above two find a relation between load, effort and trigonometric ratio of the angle of inclination.
(vi) Observe that the load is constant, and find theeffort in the two cases.
(vii) Relate mechanicaladvantage to the length of the plane and theheight of the plane.
(viii) Ratio of the efforts `= sqrt(6) : 2`
LENGTHOF the PLANK in the first case = 5.773 m
Length of the plank in the SECOND case = 7.07 m


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