1.

Find the resistance of a bulb, on which 60W and 120 V is marked.

Answer»

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SOLUTION :P = 60W, V = 120 V
We know P = VI
`rArr(V_(2))/(R)(becauseI=(V)/(R))`
`rArrR=(V_(2))/(R)=(120xxcancel(120))/(CANCEL(60))=240Omega.`


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