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Find the second derivative of sin 3 x cos 5x |
Answer» y = \(\cfrac12\) [sin(5x + 3x) + sin(5x - 3x)] y = \(\cfrac12\) sin 8x + \(\cfrac12\) sin 2x Differentiating with respect to x \(\cfrac{dy}{d\text x}\) = \(\cfrac82\) cos 8x + \(\cfrac22\) cos 2x ⇒ \(\cfrac{dy}{d\text x}\) = 4 cos 8x + cos 2x Differentiating with respect to x \(\cfrac{d^2y}{d\text x^2}\) = -32 sin 8x - 2 sin 2x Hence Proved |
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